Parse String — Basic
Use parseString() to validate a string against a template and parse it into a typed object. Property selectors provide full IntelliSense.
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Assign a validation result to a variable to see output here, e.g.
const result = schema.validate(data)Inferred Type
Define a schema to see its inferred TypeScript type.
InferType<typeof schema> automatically derives the TypeScript type from your schema definition.